2x^2+10x+25=225

Solution for 2x^2+10x+25=225 equation:

2x^2+10x+25=225

We move all terms to the left:

2x^2+10x+25-(225)=0

We add all the numbers together, and all the variables

2x^2+10x-200=0

a = 2; b = 10; c = -200;
Δ = b2-4ac
Δ = 102-4·2·(-200)
Δ = 1700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1700}=\sqrt{100*17}=\sqrt{100}*\sqrt{17}=10\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10\sqrt{17}}{2*2}=\frac{-10-10\sqrt{17}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10\sqrt{17}}{2*2}=\frac{-10+10\sqrt{17}}{4}
$